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Simplifying -50 + 23c + c2 = 0 Solving -50 + 23c + c2 = 0 Solving for variable 'c'. Factor a trinomial. (-25 + -1c)(2 + -1c) = 0Subproblem 1
Set the factor '(-25 + -1c)' equal to zero and attempt to solve: Simplifying -25 + -1c = 0 Solving -25 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '25' to each side of the equation. -25 + 25 + -1c = 0 + 25 Combine like terms: -25 + 25 = 0 0 + -1c = 0 + 25 -1c = 0 + 25 Combine like terms: 0 + 25 = 25 -1c = 25 Divide each side by '-1'. c = -25 Simplifying c = -25Subproblem 2
Set the factor '(2 + -1c)' equal to zero and attempt to solve: Simplifying 2 + -1c = 0 Solving 2 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1c = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1c = 0 + -2 -1c = 0 + -2 Combine like terms: 0 + -2 = -2 -1c = -2 Divide each side by '-1'. c = 2 Simplifying c = 2Solution
c = {-25, 2}
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